THE VERTICES OF TRIANGLE ABC ARE A(4,6) , B(1,5) , C(7,2). A LINE  IS DRAWN TO INTERSECT SIDES AB AND AC AT D AND E RESPECTIVELY SUCH THAT AD/AB=AE/AC=1/4. CALCULATE THE AREA OF TRIANGLE ADE AND COMPARE IT WITH AREA OF TRANGLE ABC.

Hi!
Here is the answer to your question.
 
A (4, 6), B (1, 5) and C (7, 2) are the vertices of the ΔABC. D and E are points on AB and AC such that

  • 170

Hey.. Arvind since AD /AB = AE/ AC, Hence the triangles r similar by thales theorem and the line is // Whickh proove tht D &E r midpoints .So , u fnd the coordinates of D&E with the help of section formula . And , thn area .. by taking ratio 1:1

Thumbs up plz..

  • -41

ranju u r rong. 

  • -50

BT M NT GETTIN HW 2 GT COORDINATES OF D & E???

  • -44

Hey.. Why u gave thumbs down this the right way.. Wat is the problem in tht ??

  • -47
What are you looking for?