the volume of 1.5m h3po4 solution required  to neutralize exactly 90 ml of a 0.5m ba(oh)2 solution is

Dear ‚ÄčKrishana Vamsi,

The volume can be calculated as follows:N1V1 (equivalents of acid)=N2V2 (equivalents of base)For H3PO4; if M=1.5 then N=M×valency factorN1=1.5×2=3similarly Ba(OH)2 has N2=1appliying formula:3×V1=1×90V1=30 ml of H3PO4 is required for complete neutralization.Regards


 

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