The work done in slowly moving an electron of charge e and mass m from A to B along a semicircular path in vertical plane in the field of charge Q is? (Q is present at the centre of the AB i.e at the centre of diameter) Ans is -2mgr please explain how?

Dear Student, 
Please find below the solution to the asked query: 
Work done:W=Force * Displacement=- mg * 2r=-2mgr
Hope this information will clear your doubts about Work done.                       
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