The work function of caesium is 2.14eV.find a)threshold frequency.b) the wavelength of incident light if the photocurrent is brought to zero by a stopping potential of 0.60v

a)  $  = h * threshold  frequency   (  $ = work function )

2.14 * 1.6  * 10-19   =  6.6  * 10-34  *  threshold frequency

threshold frequency =  2.14 * 1.6 * 10-19  /  6.6 * 10-34

  = 5.2  * 1014  hertz .

b)  4.5*10-7 meter

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