the x coordinate of a point i twice the y coordinate. If p is equidistant from Q(2,-5) and R(-3,6) find the coordiantes of P

Let Px,y be the required point and Q2,-5, R-3, 6 be the given points.Now, x-coordinate of P = 2 × y coordinate of Px = 2yNow, PQ = PRx-22 + y+52 = x+32 + y-62x-22 + y+52 = x+32 + y-622y-22 + y+52 = 2y+32 + y-624y2 + 4 - 8y + y2 + 25 + 10y = 4y2 + 9 + 12y + y2 + 36 - 12y2y + 29 = 452y = 45 - 292y = 16y = 8So, x = 2y = 2×8= 16So, P16, 8 is the required point.

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