The zeros of the quadratic polynomial x ²-88x+125 are
1)both positive
2)both negative
3)one positive and one negative
4)both equal

Answer :

We have equation  : x ² - 88 x +  125

And we know quadratic formula :

x  = $\frac{-b\pm \sqrt{b^2 - 4ac}}{2a}$

Here a  =  1  ,  b  =   - 88  and c =  125

So,

x  = $\frac{-\left( -88 \right)\pm \sqrt{{\left( -88 \right)}^2 - 4\times 1 \times 125}}{2 \times 1} = \frac{88 \pm \sqrt{7744 -500}}{2} = \frac{88 \pm 2\sqrt{1811}}{2}= 44 \pm \sqrt{1811} = 44 \pm 42.55$

So,

Zeros of our polynomial  x  =  44  + 42.55 = 86.55
And

x  =  44  - 42.55 = 1.45

So,

Both zeros are positive , So

Option ( 1 )                                                     ( Ans )