# There are 12 saplings to be planted in a straight line at an interval of 10 m between two consecutive saplings Jeremey can carry only 1 sapling at a time and he has to come back to the original point to take the next sapling He plants 12 saplings in this manner planting the first sapling at the original point After planting the saplings he comes back to the original point In the process what is the total distance Jeremey covers ?

$Forsapling1,nodis\mathrm{tan}ceiscoveredassheplanteditatoriginalpointandhencenoreturndis\mathrm{tan}ce.\phantom{\rule{0ex}{0ex}}Forsapling2,dis\mathrm{tan}cecovered=10m\phantom{\rule{0ex}{0ex}}Returndis\mathrm{tan}ce=10m\phantom{\rule{0ex}{0ex}}Forsapling3,dis\mathrm{tan}cecovered=20m\phantom{\rule{0ex}{0ex}}Returndis\mathrm{tan}ce=20m\phantom{\rule{0ex}{0ex}}andsoon\phantom{\rule{0ex}{0ex}}Thusthedis\mathrm{tan}cescoveredforsaplingscanberepresentedas:\phantom{\rule{0ex}{0ex}}0,2\left(10\right),2\left(20\right),...\phantom{\rule{0ex}{0ex}}i.e.0,20,40,...\phantom{\rule{0ex}{0ex}}ItrepresentsanA.P.withfirstterm0andcommondifference20.\phantom{\rule{0ex}{0ex}}Thereforetotaldis\mathrm{tan}cecoveredbyJeremeyforplanting12saplingsandcomingbacktooriginalposition\phantom{\rule{0ex}{0ex}}={S}_{12}=\frac{12}{2}\left[2\left(0\right)+\left(12-1\right)20\right]=6\left(11\right)\left(20\right)=1320m$

Hope this information will clear your doubts about topic.

If you have more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

Regards

**
**