there are 40 students in chemistry class and 60 students in physics .find the number of students which are either in physics or chemistry class in the following cases :

1. two classes meet at the same hour

2. two classes meet at the different hour and 20 students are enrolled in both subjects

Given, number of students in chemistry class nC=40And, number of students in physics class nP=60To find: The number of students which are either in pphysics or chemistry class. i.e., nCP1 When two classes meet at the same hour then students of both classes can not attainthe class. So, nCP=0Thus,nCP=nC+nP-nCP                =40+60-0                =100nCP=100
2When two classes meet at the different hour. And nCP=20Thus,nCP=nC+nP-nCP                =40+60-20                =80nCP=80

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