There are three points A,B and C at the corners of an equilateral triangle There is a point charge - Physics - Electric Charges And Fields

Question

There are three points A,B and C at the corners of an
equilateral triangle There is a point charge of 0 100microcoulomb
at A What wil be the intensity of the electric field at the
midpoint between B and C ,if the side of the triangle is 10 0cm(1
20*10 to the power 5 N/C)

Vijay Yadav · Accepted Answer

AB = BC = CA

= 10 cm

BD = DC = 5 cm

$AD = \sqrt{{AC}^{2} - {CD}^{2}} = \sqrt{100 - 25} = \sqrt{75}$

= 8.66 cm = 8.66 × 10^{– 2} m

Charge at AQ = 0.1 µ C = 0.1 × 10^{– 6} C

$E = K. \frac{Q}{(AD)^{2}} = 9 \times 10^{9} \times \frac{0.1 \times 10^{- 6}}{(8.66 \times 10^{- 2})^{2}} = \frac{9 \times 10^{2}}{75 \times 10^{- 4}} = \frac{90}{75} \times 10^{5} {E = 1.2 ×10}^{5} \frac{N}{C}$

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There are three points A,B and C at the corners of an equilateral triangle .There is a point charge of 0.100microcoulomb at A .What wil be the intensity of the electric field at the midpoint between B and C ,if the side of the triangle is 10.0cm(1.20*10 to the power 5 N/C)