There is a small hole in a table. A string of length 1 m passes through it. Two bodies of masses 70g and 100g are attached at its ends. The 100g mass  hangs freely at a depth of 60 cm from the table. If this mass is to be in equilibrium, the other mass should rotate in a circle with a frequency equal to
(1) 4 π 140 Hz               (2) π 140 Hz               (3) π 140 Hz                 (4) 140 4 π Hz

Dear Student,


the tension should be in the string to balance the weight of 100 gm T=0.1g=1Nlet the angualr speed be ωT=0.07ω21-0.6ω=10.07*0.4=5.98 rad /sω=2πff=5.982π HzRegards

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