This one is hard to solve pls find solution with an explanation Share with your friends Share 0 Vipra Mishra answered this Dear Student As given kinetic energy is same for both12mAvA2 =12mBvB2 vA2vB2 =mBmA =520NowF=2 kg.wt = 2×9.8 N =19.6 NF= maaA =19.6 20 vA = u+aAtA =aAtAaB =19.6 5vB = u+aBtB =aBtBaAtA2aBtB2 =52019.6 20 tA219.6 5tB2 =5205 tA220 tB2 =520tA2 tB2 =205 =4tA tB =2 Regards 0 View Full Answer