THIS Q WAS ASKED IN IIT EXAM MERITANATION

SOLVE IF sin-1x + sin-1y + sin-1z =3pi/2

then solve x1000+y2001+z300-9/x+y+z =1

U GAVE ME THE ANSWER THAT THIS QUESTION MIGHT BE WRONG BUT I HAVE FOUND OUT IT


Good to know that you have got your answer.

  • 1

we know the range of sin-1 is[ -pi/2 to pi/2] 
so the max val sin-1 can hav is pi/2
sin-x=pi/2 similarly sin-z=pi/2 sin-y= pi/2

adding  pi/2+pi/2+pi/2=3pi/2
therefore x=sin pi/2
y==sin pi/2
z==sin pi/2

therefore x=y=z=1
1+1+1-9/3=0

sry ma qust shud be equal to 0

  • 0
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