Three capacitors 3uF, 10uF and 15uF are connected in series to a voltage source of 100V. The charge on 15uFis.

Effective capacitance:1C=1C1+1C2+1C31C=13+110+1151C=1030+330+2301C=1530C=2 μFCharge on each capacitor of the combination is same and equal to the charge of the combination since all the capacitors are in series:Charge on 15 μF capacitor:Q=CV   =15×100    =1500 μC   

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in series connection charge remains constant and here it is (15uF x 100)C
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When in series the charge stored in each capacitor is same, But the voltage difference between each capacitor will be different, Hence first you need to find the equivalent capacitance (say C) and then find the charge as Q=Cx100 ( u will get C as 2 check)
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