Three containers A,B, and C of equal volume contain Oxygen,neon and methane respectively at the same temperature and pressure.The increasing order of their mass is - (A) A<B<C (B) B<C<A (C) C<A<B (D) C<B<A
n = mass/ molar mass
mass = molar mass x n (n is constant in this case as temperature , volume and pressure are constant)
mass of oxygen = 32 n
mass of neon = 19 n
mass of methane =16 n
So, increasing order of their mass is oxygen >neon>methane