Three containers A,B, and C of equal volume contain Oxygen,neon and methane respectively at the same temperature and pressure.The increasing order of their mass is - (A) A<B<C (B) B<C<A (C) C<A<B (D) C<B<A

n = mass/ molar mass

mass = molar mass x n (n is constant in this case as temperature , volume and pressure are constant)

mass of oxygen = 32 n

mass of neon = 19 n

mass of methane =16 n

So, increasing order of their mass is oxygen >neon>methane

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