three equal weight of mass 2 kg are hanging with strings passing over pulley . what is tension in string connecting B and C?






Let the required tension be T and the tension in the string connecting A and B be T 

equations are: 

for C = 2 g - T = 2 a            (i) 

for B = 2 g + T - T 1 = 2 a           (ii) 

and T 1 - 2 g = 2 a        (iii) 

adding (i), (ii), (iii) 

2 g = 6 a or a = g/3 

substituting in (i) = T = 2(g -a) = 2(g - g/3) = 4 g/3 

= 4(9.81)/3 = 13.08 N 
  • 156
thnx


 
  • -18
Ans:13 n
  • 2
3 Colgate awaits abc of mass 2 kg each and hanging on a string passing over a v frictionless Pulley as shown tension in the string connecting weights b and c

  • 32
Please find this answer

  • -6
Simply , a= net force /total weight a = 4g-2g/2kg+2kg+2kg=10/3 a=10/3 Now Tension between B and C = m(g - a) = m(g - g/3) = 2(2g/3) = 4g/3. (g = 10) = 40/3 = 13.3N
  • 6
A block of mass M1 rests on a horizontal table as 3 tattoo the block is passed on a frictionless Pulley fixed at the end of the table and the another other end of a string is hung another block of mass M the acceleration of the system is
  • 0
What are you looking for?