Three numbers are chosen at random without replacement from {1 , 2, 3,...8} .The propability that thier minimum is 3 , given that their maximum is 6. is ..ans. is 1/5.
plzz explain..
Let A be the even that 6 is maximum and B be the event that 3 is minimum,
P(A)= 5C2/ 8C3 (number less than 6 are 5
P(B)= 5C2/ 8C3 (number greater than 3 are 5)
P(A int B)= 2C1/ 8C3
Hence P(B|A)= 1/5