Three positive integers a1,a2,a3 are in AP such that a1+a2+a3=33 and a1*a2*a3=1155 find the integers

 

Dear Student

Let d be
 the common difference of the A.P.
In A.P., the difference between the consecutive terms is constant.
a1 = a2d, a3 = a2 + d
If d = 4, then a1 = 11 – 4 = 7, a2 = 11 and a3 = 11 + 4 = 15
If d = –4, then a1 = 11 + 4 = 15, a2 = 11 and a3 = 11 – 4 = 7
 
Regards

 

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