# Three positive integers a1,a2,a3 are in AP such that a1+a2+a3=33 and a1*a2*a3=1155 find the integers

*Dear Student*

Let d bethe common difference of the A.P.

Let d be

In A.P., the difference between the consecutive terms is constant.

∴

*a*_{1}=*a*_{2}–*d*,*a*_{3}=*a*_{2}+*d*If

*d*= 4, then*a*_{1}= 11 – 4 = 7,*a*_{2}= 11 and*a*_{3}= 11 + 4 = 15If

*d*= –4, then*a*_{1}= 11 + 4 = 15,*a*_{2}= 11 and*a*_{3}= 11 – 4 = 7Regards

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