1. Three resistors are connected as shown in the diagram. Through the resistor 5 ohm, a current of 1 ampere is flowing.
    1. What is the current through the other two resistors?
    2. What is the p.d. across AB?
    3. What is the total resistance?

total resistance = 1/10 + 1/15 + 5 = 11 ohm
I = 1A
V =IR
V= 1 * 5 = 5V (ACCROSS AB)
V = 1 * 11 = 11V (ACCROSS AC)
V (ACCROSS BC i.e OTHER 2 RESISTORS) = 11 - 5 =6V (AC-AB=BC)

I = V/R
I1 = 6/10 = 0.6
I2= 6 / 15 = 0.4 A

PLZZ THUMBS UPP!!!!!!!!!!!

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