three waves of equal frequency having amplitudes 10,4and 7 micrometre arrive at a given point with successive phase differnce of, pie/2, the amplitude of the resulting wave in micrometre is given by?

Let the waves be
x1 = 10sin(ωt)
x2 = 4sin(ωt+π/2)
x3 = 7 sin(ωt+π)
Thus,
x2 = 4cos(ωt)
x3 = -7 sin(ωt)
Resultant disturbance by superposition theorem  is given by
x = x1 + x2 + x3
x = 10sin(ωt) + 4cos(ωt) - 7 sin(ωt)
  = 3 sin(ωt) + 4cos(ωt)
Let R be the resultant amplitude
   3 = RcosΦ
  4 = RsinΦ
x = RcosΦ sin(ωt) + RsinΦ cos(ωt)
=> x = Rsin(ωt + Φ)
 R = √(32 + 42)
  = 5 μm  

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