To 10ml of 1M BaCl2 solution 5ml of 0.5M H2SO4 is added ,BaSO4 is precipitated out.The amount of BaSO4 ppt will be ?

Dear Student


10ml of 1M BaCl2 solution + 5ml of  0.5M H2 SO4 -----> precipitated BaSO4

Calculate the amount of BaSO4 ?
 
Reaction will be:

(10ml) BaCl +  (5ml) H2SO4 ------>  (?) BaSO4 + 2HCl
1 mol              +         1 mol      -------->   1 mol         + 2 mol
 10 gm             +          5 gm      -------->      ?           


Because 1 mL = 1 gm, therefore, Mass of BaCl2 = 10 gm and Mass of H2SO4 = 5 gm


Molarity =no. of molesvolume

No. of Moles of BaCl= MassMolarMass
                                   = 10 gMolar mass

[Molar Mass of BaCl 2 = 208.23 g/mol]

No. of Moles of BaCl210g208.23 g/mol
                                   = 0.0480 mol


Molar Mass of BaSO4 = 233.38 g/mol

Molarity = 0.048010 = 0.0048 M

Therefore, 0.0048 = Mass233.38               
Mass of BaSO4 = 0.0048 x 233.38
                         = 1.120 gm




Regards

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