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To divide a line segment AB in the ratio 2 : 9, a ray AX is drawn first such thatBAX is an acute angle and then points A_{1}, A_{2}, A_{3}, ......... are located of equal distance on the ray AX and the point B is joined to : (1) A_{8} (2) A_{11} (3) A_{3} (4) A_{12}

When , we want to divide line segment in ratio of 2 : 9 , And

A ray AX is drawn first such tha tBAX is an acute angle and then points A1 , A2 , A3, ......... are located of equal distance on the ray AX and the point B is joined to :

Point A

_{11}, And A line parallel to BA

_{11}from point A

_{2}, that intersect our line AB at C , SO :

AC : CB = 2 : 9

So ,

**Option ( 2 ) ( Ans )**

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