to smooth cylindrical basking WH Linux to each other and contact similar 3rd bar is placed over the to baisa shown in figure neglecting friction the minimum horizontal force on each slower banasa to them together is

Dear student,
Figure shows how the normal forces are acting on bottom bars.
Triangle formed by connecting the 3 centers of circle is equilateral triangle.
 
From forces acting on vertical direction, we have 2×N×cos30 = w or begin mathsize 12px style N space equals space fraction numerator W over denominator 2 space cos 30 space end fraction space equals space fraction numerator W over denominator square root of 3 end fraction end style
F = N sin30 begin mathsize 12px style equals fraction numerator W over denominator 2 square root of 3 end fraction end style,
ans is option d
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Regards.

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