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 total no. of electron present in 18 mL of water (density of water is 1g/mL) is

Since density of water is 1 gm/cc, 18 ml corresponds to mass m =18 g of water.

so, no. of moles corresponding to 18 g = m/A = 1, where  A is molecular wt (water =18 g)

Now, 1 mole of water contains 6.022*10^23 molecules of H2O and

one molecule of H2O contains 10 electrons (i.e. There are 8 electrons in oxygen and 1 from each hydrogen so a water molecule has 10 electrons).

Hence, total no. of electrons present in 18 ml of water =10 * 6.022*10^23

   = 6.022*10^24

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18 mL water X 1 g/mL = 18 g water

moles H2O = 18 g / 18 g/mol = 1 mole H2O

Number of H2O molecules = 1 mol X 6.02X1023 molecules/mole= 6.02X1023 molecules

Total electrons in 1 H2O molecule = 10 electrons/molecule 

So, 6.02 X 1023 molecules X 10 electrons/molecule = 6.02 X 1024 electrons
     6.02 X 1024 electrons are present in 18mL of water.
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how can we get the 10 electron of H2O molecules?

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