TRIANGLE PQR CONGRUENCE TRIANGLE LMN ,ANGLE Q=M=90 DEGREE,PQ=4CM & QR=3CM. FIND LN? Share with your friends Share 0 Manbar Singh answered this In ∆PQR, we havePQ = 3 cm; QR = 4 cmNow, PR2 = PQ2 + QR2 Pythagoras theorem⇒PR2 = 32 + 42⇒PR2 = 9 + 16⇒PR2 = 25⇒PR = 5 cmSince, ∆PQR≅∆LMN⇒PR = LN CPCT⇒LN = 5 cm 0 View Full Answer Aritmay Datta answered this ∆PQR is congruent to ∆LMN. So, PQ=LM QR=MN PR=LN By RHS congruency rule- (PQ)square + (QR)square =(PR)square =(4)square + (3)square =(PR)square =16 + 9 = 25 √25 = 5 cm. PR = LN :length of side LN is 5 cm. 0
