Two adjacent sides of a parallelogram are such that one is twice the other. If the perimeter of the parallelogram is 120 m. Find the length of its adjacent sides.

Let ABCD be the parallelogram.Let AB = x mNow, BC = 2x mPerimeter = 120 m2AB+BC = 120AB + BC = 60x+2x = 603x = 60x = 20So, AB = 20 mBC = 2x = 2× 20 = 40 m

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