Two balls are thrown from top of a cliff of unknown height with equal initial speed v= 10m/s one is projected at an angle 45 degree above the horizontal and second is projected at the same angle below the horizontal. What is the difference between range (in m) of projectiles?
A) 30
B) 10
C) 20
D) 12

Dear student,
Two stones are thrown off the cliff with identical initial speeds v0, but at equal angles that are below and above the horizontal. Conceptual Example 9 compares the velocities with which the stones hit the water below.

The difference in ranges is given by 
R=v2sin2θ/gR=(10)2sin 2×45/10R=100sin90/10R=10 m

Option b is correct

Regards

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