Two blocks are in contact on a frictionless table. One has mass m and the other 2m. A force F is applied on 2m as shown in figure. Now the same force F is applied from the right on m. In the two cases the ratio of force of contact between the two blocks will be (1) 1 : 1 (2) 1 : 2 (3) 2 : 1 (4) 1 : 3

Dear Student,


Please find below the solution to the asked query:

If F is the applied force then acceleration of the system is F2m+m=F3m.
Now when we are applying the force from the left, the force applied on the block m is F3mm=F3. This will be the force in the contact.
When we apply the force from the right from on the block will be F3m2m=2F3, this will be the force on the contact then.
So the ratio is F3:2F3=1:2

Hope this information will clear your doubts about force.


If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.




  • 63
  • -43
What are you looking for?