# Two blocks are in contact on a frictionless table. One has mass m and the other 2m. A force F is applied on 2m as shown in figure. Now the same force F is applied from the right on m. In the two cases the ratio of force of contact between the two blocks will be (1) 1 : 1 (2) 1 : 2 (3) 2 : 1 (4) 1 : 3

Dear Student,

If F is the applied force then acceleration of the system is $\frac{F}{2m+m}=\frac{F}{3m}$.
Now when we are applying the force from the left, the force applied on the block m is $\frac{F}{3m}m=\frac{F}{3}$. This will be the force in the contact.
When we apply the force from the right from on the block will be $\frac{F}{3m}2m=\frac{2F}{3}$, this will be the force on the contact then.
So the ratio is $\frac{F}{3}:\frac{2F}{3}=1:2$