# two bodies of mass 1 kg and 100 kg respectively are dropped simultaneously fron same height 4.9 m in vacuum. Calculate and comapre their final velocities just before hitting the ground and the time interval in which they will hit the ground (g= 9.8m/s2)

Mass of first body = 1 kg

Mass of second body = 100 kg

Height from where the bodies have been dropped =  4.9 m

Remember this is all happening in Vaccum.

Now since the only force acting on the bodies is the gravity and there is no air resistance inside the vaccum

Final velocity and Time interval in which they will hit the ground will be same for both the bodies.

Initial velocity for both the bodies = 0 m/s since both the bodies are being dropped from rest at some height.

Now using Newton's equation of motion:

v2 = u2 + 2gs

we get, v = 9.8 m/s

From equation, v = u + gt

we can have t = 1 sec.

Hope it helps!

• -1

u=0

h=4.9

g=9.8m/sec2

2gh=v2-u2

2*9.8*4.9=v2-0

96.04=v2

v=√96.04

v=9.8m/sec2

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