two bodies of mass 1 kg and 100 kg respectively are dropped simultaneously fron same height 4 9 m in - Science - Gravitation

Question

two bodies of mass 1 kg and 100 kg respectively are dropped
simultaneously fron same height 4 9 m in vacuum Calculate and
comapre their final velocities just before hitting the ground and
the time interval in which they will hit the ground (g= 9
8m/s2)

nitish.gupta · Accepted Answer

Mass of first body = 1 kg
Mass of second body = 100 kg
Height from where the bodies have been dropped = 4 9 m
Remember this is all happening in Vaccum
Now since the only force acting on the bodies is the gravity and
there is no air resistance inside the vaccum
Final velocity and Time interval in which they will hit the
ground will be same for both the bodies
Initial velocity for both the bodies = 0 m/s since both the
bodies are being dropped from rest at some height
Now using Newton's equation of motion:
v2 =
u2 +
2gs
we get, v = 9 8 m/s
From equation, v = u +
gt
we can have t = 1 sec
Hope it helps!

two bodies of mass 1 kg and 100 kg respectively are dropped simultaneously fron same height 4.9 m in vacuum. Calculate and comapre their final velocities just before hitting the ground and the time interval in which they will hit the ground (g= 9.8m/s2)

two bodies of mass 1 kg and 100 kg respectively are dropped simultaneously fron same height 4.9 m in vacuum. Calculate and comapre their final velocities just before hitting the ground and the time interval in which they will hit the ground (g= 9.8m/s²)