Two buses A and B are at positions 60 m and 160 m from the origin at time t=0. They start moving in the same direction simultaneously with uniform speed 54km/h and 36km/h. Determine the time and position at which A overtaken B?

Solution:  
Two buses are  moving in same direction and the distance between them is 160-60=100mrelative velocity=v1-v2v1=54×5/18=15m/secv2=10m/secVrel=15-10=5m/secx1( t ) = x1+ v1t = 60 + 15 t x2( t ) = x2+ v2t = 160 + 10 tTime after which A overtakes Btime=distance/time=100/5=20secPosition at which A overtakes B=100+15×20=400m from origin

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