two capacitors A and B are connected in series with a 100V battery and it is observed that the potential difference across them are 40V and 60V respectively. A capacitor of capacitance 6mF is now connected in parallel with B and as a result the potential differnce across B falls to 50V. Find the capacitance of A and B.
Please find below the solution to the asked query:
Given that the total potential difference is 100 V. When the two capacitors are connected in series, then the potential drops across the two resistors are 40 V & 60 V respectively. Therefore, the charge through the two capacitors will be same in series.
Now, if a capacitance of is connected in parallel to the second capacitor, then the potential drop across A & B becomes 50 V & 50 V respectively. Here, the the charge flowing in A and in other combination will be same because those are in series. Now, the potential drops will also be same. Therefore,
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