Two capacitors of capacitance C1 = 1uF and C2=4uF are charged to 60 V by connecting them across the battery - Physics - Electrostatic Potential And Capacitance

Question

Two capacitors of capacitance C1 = 1uF and C2=4uF are charged to 60
V by connecting them across the battery Now, they are disconnected
from the battery and connected to each other with terminals of
unlike polarity together The final voltage across each capacitor
would equal to

Vara · Accepted Answer

Voltage of first capacitor: V1=60 VVoltage of second capacitor: V2=60 VVoltage of the combination:V=Total chargeTotal capacitance   =C2V2-C1V1C2+C1   =4×60-1×601+4   =36 V

Two capacitors of capacitance C1 = 1uF and C2=4uF are charged to 60 V by connecting them across the battery. Now, they are disconnected from the battery and connected to each other with terminals of unlike polarity together. The final voltage across each capacitor would equal to