# Two cars A and B Moving with same speed of 45 km/hr along the same direction .If a third car C coming from opposite direction with a speed of 36 km/hr meets two cars in an interval of 5 minutes ,then the distance of separation of two cars A and B in km ?

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${V}_{A}={V}_{B}=45km/h\phantom{\rule{0ex}{0ex}}{V}_{C}=36km/h\phantom{\rule{0ex}{0ex}}letxisthedis\mathrm{tan}cebetweenAandB..\phantom{\rule{0ex}{0ex}}velocityofapprachbetwenAandB.\phantom{\rule{0ex}{0ex}}{V}_{Ac}={V}_{A}+{V}_{B}=45+36=81km/h\phantom{\rule{0ex}{0ex}}{V}_{BC}={V}_{B}+{V}_{C}=45+36=81km/h\phantom{\rule{0ex}{0ex}}velcoityofapproach=\frac{dis\mathrm{tan}cebetwenAandB}{timedifferenceinmeetingAandB.}\phantom{\rule{0ex}{0ex}}\u2206t=5min=\frac{5}{60}hrd\phantom{\rule{0ex}{0ex}}81=\frac{x\times 60}{5}\phantom{\rule{0ex}{0ex}}x=\frac{81\times 5}{60}=6.75km$

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