Two cars A and B Moving with same speed of 45 km/hr along the same direction .If a third car C coming from opposite direction with a speed of 36 km/hr meets two cars in an interval of 5 minutes ,then the distance of separation of two cars A and B in km ?

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VA= VB=45 km/hVC= 36 km/hlet x is the distance between A and B..velocity of apprach betwen A and B.VAc=VA+VB=45+36=81 km/hVBC=VB+VC=45+36=81 km/hvelcoity of approach = distance betwen A and Btime difference in meeting A and B.t=5 min = 560 hrd81=x×605x=81×560=6.75 km
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