Two chimneys 18m and 13m high stand upright on a ground.If their feet is 12m apart,then the distance between their topsis?

Dear Student!

@imbaai: Very good! Keep posting! Thumbs up for you.

In right ΔAED,

Perpendicular, AE = 18 m – 13 m = 5 m

Base, DE = BC = 12 m

AD = Hypotenuse = Distance between the tops of the two chimneys

$\Rightarrow \mathrm{AD}=\sqrt{{\mathrm{AE}}^{2}+{\mathrm{ED}}^{2}}=\sqrt{{5}^{2}+{12}^{2}}=\sqrt{25+144}=\sqrt{169}=13\mathrm{m}$

Cheers!

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