Two chimneys 18m and 13m high stand upright on a ground.If their feet is 12m apart,then the distance between their topsis?

Dear Student!

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In right ΔAED,

Perpendicular, AE = 18 m – 13 m = 5 m

Base, DE = BC = 12 m

AD = Hypotenuse = Distance between the tops of the two chimneys

AD = AE2+ED2 = 52+122 = 25+144 = 169 = 13 m

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  • 7

 Let the distance between their tops be X.

Then if you will draw the figure you will see that the tops form a right triangle.

Perpendicular = difference of the heights of the chimneys = 18-13 = 5m

Base= Distance between their feet = 12m

Hypoteneuse = Distance between their tops 

So applying Pythagoras theorem to the triangle we proceed as follows

Hypoteneuse2 = Perpendicular2 + Base2

X2 = 52 + 122

X2 = 25+144

X2 = 169

X = √169

X = 13m

So the distance between their tops is 13m.

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  • 4
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