Two circles intersect each other at points P and Q. If AB and AC are the tangents to the circles from a point A on QP produced show that AB=AC
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We know that,
If a tangent segment and a secant intersect in the exterior of a circle, then the square of a length of the tangent segment is equal to the product of the length of the secant segments and its exterior part.
Since AB is tangent and APQ is a secant. Therefore,
Similarly, AC is tangent and APQ is a secant. So,
From (1) and (2), we have,
If a tangent segment and a secant intersect in the exterior of a circle, then the square of a length of the tangent segment is equal to the product of the length of the secant segments and its exterior part.
Since AB is tangent and APQ is a secant. Therefore,
Similarly, AC is tangent and APQ is a secant. So,
From (1) and (2), we have,