two coils have self inductance L1 = 4mH and L2= 1mH resp. the currents in the two coils are increased at the same rate. at a certain instant of time both coils are given the same power. If i1 and i2 are the currents in the two coils, at that instant of timw respectively, then the value of i1/i2 is

1) 1/8

2) 1/4

3) 1/2

4)1

Energy in an inductor is given by:U = 12LI2power = dUdtp = LIdIdtsince both have same power thereforep1 = p2L1I1dI1dt = L2I2dI2dtwhere dIdt is the rate at which current changes.L1I1 = L2I2I1I2 = L2L1 = 14

  • 40
What are you looking for?