# Two concentric spherical conducting shells of radii R and r (Rr) are supported by insulating stands. The outer shell is given a charge Qwhile the inner shell is grounded. Find the charge on the inner shellsolnPotential of the inner shell must be zero, since t is grounded. the problem is that potential of inner shell is then why here whole system potential is taken zero.Options    Answer:Potential of the inner shell must be zero, since t is grounded. QUESTION : 2The electric field and the electric potential at a point due to a point charge are 13 V/C and 8 J/C respectively. Find the magnitude of the charge and the distance of the point from the charge.Options 8.89 × 1010C, 2m 4.44 × 1010C, 2m 8.89 × 1010C, 0.5m 4.44 × 1010C, 0.5m Answer: QUESTION : 3Two charges 2×108C and 3×108C are located 30 cm apart. Determine the point from the negative charge at which the electric potential is 0.Options 18 cm 12 cm 16 cm 15 cm Answer: Potential at P ⇒ x= 0.18 mQUESTION : 4Sixty four water droplets, each of radius 1 mm and charge 1010C combine to form a single large drop. Determine the potential of the bigger drop.Options 256 V 126 V 280 V 144 V Answer:Volume of large drop = Volume of small drops QUESTION : 5Considera coordinate axis system. At origin, the potential is zero. In the positive x direction, an electric field of intensity E0is directed. Find the potential at x = +x0.Options Ex0 Ex0 2Ex0 2Ex0 Answer:For a uniform fieldΔV = EΔr. In this case,ΔV = V 0,Δr = x0 0, and E = E0.Thus,V 0 = E (x0 0)or V = Ex0 Note the negative sign. As one moves along the direction of electric field, the potential falls.Hence, optionBis correct.

Due to paucity of time, it is not possible for us to solve all of your queries. We are providing solution of your some good questions.
2. Given, electric field, E  = 13 N/C
Electric potential, V = 8J/C
​From formula :
E = $\frac{kq}{{r}^{2}}$    where r is the distance of the point from charge
13 =
V = $\frac{kq}{r}$
8 =
Dividing eq. 1 with eq. 2, we get :

Putting value of r and k = 9 X 10Nm2C-2 in eq. 2, we get :
8 =
q = 0.54 X 10-9 C

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only first question remainy bymistake got attached

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Two concentric spherical conducting shells of radii R and r (Rr) are supported by insulating stands. The outer shell is given a charge Q while the inner shell is grounded. Find the charge on the inner shell.

solnPotential of the inner shell must be zero, since t is grounded the problem is that potential of the inner shell is 0 then how we can take potential of the system as zero
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Two concentric spherical conducting shells of radii R and r (Rr) are supported by insulating stands. The outer shell is given a charge Q while the inner shell is grounded. Find the charge on the inner shell.

solnPotential of the inner shell must be zero, since t is grounded the problem is that potential of the inner shell is 0 then how we can take potential of the system as zero
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Two concentric spherical conducting shells of radii R and r (Rr) are supported by insulating stands. The outer shell is given a charge Q while the inner shell is grounded. Find the charge on the inner shell.

solnPotential of the inner shell must be zero, since t is grounded the problem is that potential of the inner shell is 0 then how we can take potential of the system as zero
• 0
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