two dice are thrown simultaneously,find the probability of getting,a) sum of two faces is prime​,b)sum of two faces is divisible by 3 and 4,c)sum of two faces greater than 6,d)a doublet

Dear student
Sample space of throwing two dice is

Total no.of outcomes of throwing a two dice=36a) Sum of two faces is primeOutcomes of getting a sum of two faces as prime are(1,1),1,2,1,4,1,6,2,1,2,3,2,5,3,2,3,4,4,1,4,3,5,2,(5,6),(6,1),(6,5)No. of favourable outcomes=15So, required probability=No. of favourable outcomesTotal no.of outcomes of throwing a two dice=1536=512c) Sum of two faces greater than 6Outcomes of getting a sum of greater than 6 are6,1,2,5,2,6,3,4,3,5,3,6,4,3,4,4,4,5,4,6,5,2,5,3,5,4,5,5,5,6,6,1,6,2,6,3,6,4,6,5,(6,6)No. of favourable outcomes=21So, required probability=No. of favourable outcomesTotal no.of outcomes of throwing a two dice=2136=712d) a doubletOutcomes of getting a doublet are1,1,2,2,3,3,4,4,5,5,(6,6)No. of favourable outcomes=6So, required probability=No. of favourable outcomesTotal no.of outcomes of throwing a two dice=636=16
Similarly try b part
Regards

  • 1
What are you looking for?