two dice are thrown simuntaneously 500 times . each time the sum of two numbers appearing on them is not written
sum frequency
2 14
3 30
4 42
5 55
6 72
7 75
8 70
9 53
10 46
11 28
12 15
find the PROBABILITY of getting a sum
1)more than 10
2)between 8 and 12
- To find the probability of getting a sum if more than 10 that is getting 11 or 12.
The total number of times the experiment is conducted is 500.
Number of times a sum of 11 occurs is 28 and the number of times the sum 12 occurs is 15.
P(getting sum more than 10) =(28+15)/500 = 43/500
P( getting sum between 8 and 12= (70+53+46+28+15)/500 = 212/500