Two dice are tossed together.Find the probability of getting a doublet or a total of 6.

s(sample space)= {(1,1) (2,1) (3,1) (4,1) (5,1) (6,1)

(2,1) (2,2) ..............so on till (6,6)}

1. Total outcomes = 36 (since.the sample space = 36)

favourable outcomes= (1,1) (2,2) (3,3 ) (4,4) (5,5) (6,6)=6

p(getting doublet) = 6/36 =1/2

P(getting total of 6)= 5/36 ( since the favourable outcomes are= (1,5) (2,4) (3,3) (4,2) (5,1) =5))