Two different dice are thrown together, the probability that the numbers
obtained have a product less than 16 is:-

Dear Student, 
Solution)
Two dices are thrown in 6x6 =36 ways
Let A be the event such that
A=Product less than 16
A={(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(4,1)(4,2)(4,3)(5,1)(5,2)(5,3)(6,1)(6,2)}
n(A)=25
$$\begin{gathered} P\left(A\right)=\frac{No. of favorable outcomes n\left(S\right)}{Total outcomes n\left(A\right)} \\ =\frac{25}{36} \end{gathered}$$
Hence Probability of getting product less than 16= $\frac{25}{36}$
Regards!