Two magnets of magnetic moments M and 31/2 M are joined to form a cross The combination is suspended - Physics - Magnetism And Matter

Question

Two magnets of magnetic moments M and 31/2 M are
joined to form a cross The combination is suspended in a uniform
magnetic field B The magnetic moment M now makes an angle
Î¸ with the field direction find the value of angle
Î¸

Vijay Yadav · Accepted Answer

Resultant of magnetic moments M and (3)0 5M is given by $M' = \sqrt{M^{2} + (\sqrt{3} M)^{2} + 2 M (\sqrt{3} M) \cos 90^{0}} = > M' = 2 M \tan α = \frac{M}{\sqrt{3} M} = \frac{1}{\sqrt{3}} = \tan 30^{0} = > α = 30^{0}$ So, Î¸ + Î² = 600 System is equilibrium so net torque will be zero $\vec{M'} \times \vec{B} = 0 = > M' B \sin β = 0 = > \sin β = 0 = > β = 0$ Hence, Î¸ + Î² = 600 => Î¸ = 600

Two magnets of magnetic moments M and 31/2 M are joined to form a cross. The combination is suspended in a uniform magnetic field B. The magnetic moment M now makes an angle θ with the field direction. find the value of angle θ.

Two magnets of magnetic moments M and 3^1/2M are joined to form a cross. The combination is suspended in a uniform magnetic field B. The magnetic moment M now makes an angle θ with the field direction. find the value of angle θ.