Two men leave a place with an interval of t between them. They arrive at one end of a
bridge of length L with time interval of T and reach the other end of the bridge at the same
time. Find the ratio of their speeds. How far is the nearer end of the bridge from their
starting point?

Dear student,

Let uniform speed of first one =vaUniform speed of second one=vbFor case CA as shown above,x+Lva-x+Lvb=t 1va-1vb=tx+L   ................................(1)For case CB,Lva-Lvb=T1va-1vb=TL.....................................(2)now equating eqn 1 and 2 we get,x=Lt-TT
Now by putting the value of x, the ratio of the velocities can be found easily.

Regards


 

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abhi to nhi pta
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