Two milk containers contains 398 l and 436 l of milk. The milk is to be transferred to another container with the help of a drum. While transferring to another container 7l and 11l of milk is left in both the containers respectively. What will be the maximum capacity of the drum.
398-7=391 and 436-11=425
now HCF of 391 and 425 is 17.
So maximum capicity of drum is 17 l .