Two milk containers contains 398 l and 436 l of milk. The milk is to be transferred to another container with the help of a drum. While transferring to another container 7l and 11l of milk is left in both the containers respectively. What will be the maximum capacity of the drum.

398-7=391 and 436-11=425

now HCF of 391 and 425 is  17.

So maximum capicity of drum is 17 l .

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