two moles of NH3 gas are introduced into a previously evacuated one litre vessel in which it partially dissociate at high temperature as 2NH3-N2+3H2.at equilibrium one mole of NH3 Remain.the value of Kc is??

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at start 2 0 0

at equi 2-1 1 1

kc=1*1cube/1square=1

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2 NH N 3 H 3 22 t0 2 0 0 Equilibrium 2 2x x 3x    - - - - - - 2 – 2x = 1  x = 0.5         3 3 c 2 2 x 3x 0.5 1.5 75 27 K 0.75 100 16
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At eq 2-2x. x. 3x but 2-2x = 1 =>x=•5 Kc= [N2][H2]^3/[NH3]^2 =(x)(3×.5)^3/(2-2x)^2 =1.5
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Answer

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electronegativety
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solid state
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cell
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If will be calculated this way

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It can be solve in this way

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Please find this answer

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Its 27/4
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Please answer the questions no. 14

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sab aakash wale ha
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