Two numbers are 20% and 25% less than a third number respectively. how much % is the second number less than the first number ?

Let B is 20% less than A , and C be 25% less than A.

Let A be x, then

B =

*x*- 20% of

*x*=

*x*- ( 20/100 )

*x*= 80

*x*/100 = 0.8

*x*

C= x - 25% of x =

*x*- 25/100

*x*= 75

*x*/100 = 0.75

*x*

Now we have to find out how much % C is less than B so

$=(0.8x-0.75x)/0.8x*100\phantom{\rule{0ex}{0ex}}=(0.05x/0.8x)*100\phantom{\rule{0ex}{0ex}}=100/16\phantom{\rule{0ex}{0ex}}=6.25\%$

**(answer)**

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