Two particles A and B are in motion. If the wavelength associated with particle A is 5x10^-8m, calculate wavelength associated with B if its momentum is half of A
The relation between wavelength and momentum of moving particle is given by
Momentum = h/wavelenth
p = h/lambda
Wavelength of the particle A = 5 x 10-8 m
Let the momentum of particle A is pA and the momentum of the particle B is pB
Relation between pA and pB is :
pB = pA/2
pA = h/ 5 x 10-8 m
pB = h/ 5 x 10-8 m x 2
Wavelength of B(lambda) = h/pB
= h/ h/ 5 x 10-8 m x 2
= 10 x 10-8 m
= 10-7 m
Momentum = h/wavelenth
p = h/lambda
Wavelength of the particle A = 5 x 10-8 m
Let the momentum of particle A is pA and the momentum of the particle B is pB
Relation between pA and pB is :
pB = pA/2
pA = h/ 5 x 10-8 m
pB = h/ 5 x 10-8 m x 2
Wavelength of B(lambda) = h/pB
= h/ h/ 5 x 10-8 m x 2
= 10 x 10-8 m
= 10-7 m