Two particles A and B are moving in XY-plane. Their positions vary with time t according to relation:
xA(t) = 3t, x​B(t) = 6
yA(t) = t, yB​(t) = 2 + 3t2
Distance between two particles at t = 1 is:
(1) 5
(2) 3
​(3) 4
(4) 

Dear student,at t=1xa=3×1=3xb=6ya=1yb=2+3×12=5(xa,ya) and (xb,yb) will be (3,1) and (6,5)distance between these two=(6-3)2+(5-1)2D=5option (1) is correctRegards

  • 14
What are you looking for?