Two particles A and B are moving in XY-plane. Their positions vary with time t according to relation: xA(t) = 3t, xB(t) = 6 yA(t) = t, yB(t) = 2 + 3t2 Distance between two particles at t = 1 is: (1) 5 (2) 3 (3) 4 (4) Share with your friends Share 8 Decoder_2 answered this Dear student,at t=1xa=3×1=3xb=6ya=1yb=2+3×12=5(xa,ya) and (xb,yb) will be (3,1) and (6,5)distance between these two=(6-3)2+(5-1)2D=5option (1) is correctRegards 14 View Full Answer