Two particles a and b of masses 1 and 2 kg resp are kept 1m apart and are released - Physics - Gravitation

Question

Two particles a and b of masses 1 and 2 kg resp are kept 1m apart
and are released to move under mutual attraction Find the speed of
a when that of b is 3 6cm/hour What is the separation between
particles at this instant?

Decoder_2 · Accepted Answer

Dear
student,

The force of attraction between the two bodies of masses 1Kg and 2Kgseparated by distance 1m =F = G×1×21=2GThe force of particle of mass 2Kg on 1Kg mass=2a=2GOR               a=Gor                   dvdt=Gor                      dvdx×dxdt=Gor                       ∫  v dv =∫G dxor                          vb22=Gx----1Now whenspeed of particle B is vb=3
6cm/h=3
6100×60×60=10-5m/sthen       x = vb22G=10-102×6
67×10-11=56 67=0
75mtherefore the instant velocity of particle B is 3
6cm/h, the separation of A and B is 0
75m
In order to find the velocity of particle A , the velocity of particle A is,              va22=2Gxputting the value of Gx from eqn 1 in above eqn, we ge            va22=2×6
67×10-11×0
75   or                  va2=3×6
67×10-11=20 01×10-11=2
001×10-10or                  va = 1
4×10-5m/s     
Regards

Two particles a and b of masses 1 and 2 kg resp. are kept 1m apart and are released to move under mutual attraction. Find the speed of a when that of b is 3.6cm/hour. What is the separation between particles at this instant?