Two particles are projected simultaneously as shown in fig Particle A is projected at an angle 45º with a - Physics - Electric Charges And Fields

Question

Two particles are projected simultaneously as shown in fig Particle
A is projected at an angle 45º with a speed of 10m/s,
from the top of a l0m tower Another particle B, is projected
horizontally with a speed 10m/s from a 30 m long tower What should
be the horizontal distance 'd' between them, so as they collide in
the mid air :-

(1)20 m(2)30 m(3)40 m(4)50 m

Neha Gupta · Accepted Answer

Let they meet after time time t
vertical distance travelled by horizontal projectile is y
y = ut+12at2y = 0 + 0
5×10t2vertical distance travelled by angular projectile is 20-y20-y = uxt - 12gt220-12gt2 = 102×12- 12gt2t = 2 sHorizontal distance travelled in 2seconds
x1 = ut  = 10×2 = 20 mx2 =uxt = 102×12×2 = 20 md = x1+x2 = 20+20 = 40 m