Two particles of mass m1 and m2 in projectile motion have velocities v1 and v2 respectively at time t=0. They collide at timet0 Their velocities become v1' and v2' at time 2t0 while still moving in air. The value of mod (m1v1'+m2v2') -(m1v1+m2v2) is

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change in momentum=02t0F.dt =mg×2t0 =2(m1+m2)gt0since only force acted during projectile is due to gravity .Regards 

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